r^2/5-2r^1/5-3=0

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Solution for r^2/5-2r^1/5-3=0 equation: 


r in (-oo:+oo)

(r^2)/5-((2*r^1)/5)-3 = 0

(r^2)/5+(-2/5)*r-3 = 0

1/5*r^2-2/5*r-3 = 0

DELTA = (-2/5)^2-(-3*1/5*4)

DELTA = 64/25

DELTA > 0

r = ((64/25)^(1/2)+2/5)/(1/5*2) or r = (2/5-(64/25)^(1/2))/(1/5*2)

r = 5 or r = -3

r in { -3, 5 }

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